Question

Please give me answer of questions 5 of the attachment

Answer 1

Consider triangle abd, acd

Ad=ad(common)

Ab=ac(since chords are equidistant from the centre)

Angle abd=angle acd=90( the diameter form a right angle in a semicircle.)

Therefore triangle abd congruent to triangle acd by rhs criteria.

Therefore angle bad=angle dac and angle bda = angle adc by cpct.