Question

please give me answer of this question​

Answer 1

Answer:

Step-by-step explanation:

∫ cos^2x dx = ∫(cos2x+1)/2 dx =  ∫cos2x/2dx + 1/2∫dx

                         let t = 2x

                      dt/dx = 2

            ∫costdt/2+1/2*x =  sint/2+x/2 = 0[(sin2x)/2+x/2]π

               =  (sinπ)/2+π/4-sin0-0 = π/4   Ans         ......[sinπ = 0] , [sin0 = 0]