Math, asked by ak9027015, 5 months ago

please give me answer of this question​

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Answered by kochrekarprathamesh5
2

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Angle ACB =

Angle ACD + Angle ACB = 180°

Angles are in linear pair

128° + Angle ACB = 180°

Angle ACB = 180 - 128

Therefore, Angle ACB = 52°

Angle ABC + Angle ACB + Angle BAC = 180°

43 + 52 + Angle BAC = 180°

Angle BAC = 180 - 95

Therefore,

Angle BAC = 85°

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