Math, asked by Uttkersh65, 10 months ago

please give me answer of this question​

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Answered by z5113
1

sum of angles of triangle =180

ADB=(2y+3)+(9y+3)+(3y-y) =180

=2y+3+9y+3+3y-y=180

=2y+9y+3y-y+3+3=180

14y-y+6=180

13y+6=180

=13y=180-6

=13y=174

=y=174/13

=y=58

CDB

(9a+3)+(4a+3)+(2a+7)=180

9a+3+4a+3+2a+7=180

9a+4a+2a+3+3+7=180

15a+13=180

15a=180-13

15a=167

a=167/15

a=11.1333333

I am still not sure about angle( 2a+ ) in CDB because I couldn't understand whether it is 2a+1 or 2a+7

hope this helps

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