Question

please give me answer of this question this question is from the lesson similarity of class 10th from geometry subject

Answer 1

Hi ,

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we know that ,


area of the triangle = ( bh )/2

where ,

b = base ,

h = corresponding height

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It is given that ,

<ABC = <DCB = 90°

AB = 6 ,

DC = 8 ,

∆ABC/ ∆DCB = [ ( BC × AB )/2 ]/[ ( BC × DC )/2 ]

= AB/DC

= 6/8

= 3/4

I hope this helps you.

: )

Answer 2

heya...!!!!!

given that:-

<ABC = 90°

so the area of triangle
= 1/2(base × perpendicular height

=> area of ∆ABC = 1/2(AB × BC)

=> 1/2(6 × BC)

similarly,

<DCB = 90°

area of ∆DCB= 1/2(8 × BC)

NOW,


(area of∆ABC) / (area of ∆DCB) = [1/2(6 × BC) / 1/2(8 × BC)]

=> (6×BC)/(8×BC)

=> 6/8