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In triangle XYZ, ∠Y is right angle, XZ = 17 cm and YZ = 15 cm, then find
( i ) sin X
( ii ) cos Z
( iii ) tan X
Solution:
In right ∆XYZ
By using Pythagoras theorem,
XZ² = XY² + YZ²
17² = XY² + 15²
289 = XY² + 225
XY² = 289 - 225
XY² = 64
XY = √64
XY = 8 cm
Now,
( i ) sin X
sin X = YZ/XZ
sin X = 15/17
( ii ) cos Z
cos Z = XY/XZ
cos Z = 15/17
( iii ) tan X
tan X = YZ/XY
tan X = 15/8
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