Question

please give me answer !! urgent

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Answer 1

I) 1,1

p(x)= k(x² - ( sum of zeroes)x + (product of zeroes)

=[x²-(1)x + (1)]

=x²-x+1

similarly

p(x)= k(x² - ( sum of zeroes)x + (product of zeroes)

=x²-4x+1

Answer 2

×– Quadratic polynomial –×

➜ (iv) 1 , 1 ( these are zeros )

so now,

✧ œ + ß = 1 { here we assume that œ = Alpha )

œ ß = 1

✧ œ + ß = -b = 1

a 1

✧ œ ß = c = 1

a 1

hence , b = - 1 , a = 1 , c = 1 { - b = 1 so, b = - 1 }

ax²+ bx + c = 0

x² - x + 1 = 0

➜ (vi) 4 , 1

✧ œ + ß = 4

œ ß = 1

✧ œ + ß = - b = 4

a 1

✧ œ ß = c = 1

a 1

hence, b = - 4 , c = 1 , a = 1 { - b = 4 so, b = - 4 }

ax² + bx + c = 0

x² - 4x + 1 = 0

I hope it helps you