Question

please give me answers​

Answer 1

sin 2A + sin 2B = 2 sin (A+B) cos (A-B)

sin 2A - sin 2B = 2 sin (A-B) cos (A+B)

$= \frac{2 \sin(a + b) \cos(a - b) }{2 \sin(a - b ) \cos(a + b) } \\ = \tan(a + b) \cot(a - b) \\ = \frac{ \tan(a + b) }{ \tan(a - b) }$

Hence proved

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