Math, asked by kaur353472, 11 months ago

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Answered by viraajrao05
1

Step-by-step explanation:

1. ∵∠ADC=∠DCA

∴AD=DC (Base angles of isoceles Δ are equal)

∵ ABCD Is a Rectangle

∴AB=CD, BC= AD

∵AD=DC

∴AB= BC =CD=DA

∵All angles of a rectangle are 90

∴ABCD is a square

2. Construct  Diagonal BD

in a square all sides are equal

∴BC= CD

∴∠CDB=∠CBD - 1( Base angles of isoceles Δ are equal

similiarly  in ΔBDA

∠ABD=∠ADB - 2

∵∠ABD= ∠CDB (alternate interior angles)

∴∠ABD= ∠CDB=∠ADB=∠CBD (from 1 and 2)

∴BD BISECTS ∠B and ∠D

Answered by rayyan240606
0

Answer:

1. ∵∠ADC=∠DCA

∴AD=DC (Base angles of isoceles Δ are equal)

∵ ABCD Is a Rectangle

∴AB=CD, BC= AD

∵AD=DC

∴AB= BC =CD=DA

∵All angles of a rectangle are 90

∴ABCD is a square

2. Construct  Diagonal BD

in a square all sides are equal

∴BC= CD

∴∠CDB=∠CBD - 1( Base angles of isoceles Δ are equal

similiarly  in ΔBDA

∠ABD=∠ADB - 2

∵∠ABD= ∠CDB (alternate interior angles)

∴∠ABD= ∠CDB=∠ADB=∠CBD (from 1 and 2)

∴BD BISECTS ∠B and ∠D

Read more on Brainly.in - https://brainly.in/question/13761673#readmore

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