please give me any 1 from this 2 questions please
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Answer:(2)
here,
∠X+∠Y+∠Z=180............[SUM OF ANGLES OF TRIANGLE]
or,(a+30)+90+a=180
or,2a=60
∴a=30
so,∠X=(a+30)=60
∠Z=a=30
now,
sin(∠Z)=XY/XZ
or,XY=XZ*sin(∠Z)
=24*sin30
=12
by pythagoras theoren
XZ²=XY²+YZ²
or,YZ=√(XZ²-XY²)
=√(24²-12²)
=12√3
so, XY=12, YZ=12√3
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