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Explanation:
Proof of (d/dx) x^n : from (d/dx) e^(n ln x)
Given: (d/dx) e^x = e^x; (d/dx) ln(x) = 1/x; Chain Rule.
Solve:
(d/dx) x^n = (d/dx) e^(n ln x)
= (d/du) e^u (d/dx) (n ln x) (Set u = n ln x)
= [e^(n ln x)] [n/x] = x^n n/x = n x^(n-1)
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