Math, asked by ikramkolekar045, 3 months ago

please give me exact answer​

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Answered by ShivayRSahu
1

Answer:

haysgwvshwhsbw

261. +  \leqslant 1 \geqslant  \geqslant  <  \sqrt[ {21 { {2x { { { {23144}^{2} }^{2} }^{?} }^{?}  \times \frac{?}{?} }^{2}  \times \frac{?}{?} }^{2}  \times \frac{?}{?} }^{?} ]{?}

hsbs

Step-by-step explanation:

.x134.4 {1 { \leqslant  \leqslant  \sqrt[ | \times .1 \times .2x \times \frac{?}{?}  \times \frac{?}{?}  \times \frac{?}{?} | ]{?}  \times \frac{?}{?} }^{2} }^{2}  \times \frac{?}{?}  \times \frac{?}{?}  \times \frac{?}{?}

.x134.4 {1 { \leqslant \leqslant \sqrt[ | \times .1 \times .2x \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} | ]{?} \times \frac{?}{?} }^{2} }^{2} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?}

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