Question

please give me fast okkk

Answer 1

Answer:

( - 2z + 7)

Step-by-step explanation:

First of all lets rearrange Dividend into standard form which is

- 6z² + 29z - 28

or - (6z² - 29z + 28)

Multiply constant term with coefficient of z², we get 168

Now find two factors of 168 which gives 29 by adding them, in this case such two factors of 168 are 21 and 8, splitting middle term

- [6z² - (21z + 8z) +28]

- [6z² - 21z - 8z + 28]

taking 3z common from first two terms and -4 from last two terms

-[ 3z(2z - 7) -4(2z -7)]

- (2z - 7) (3z - 4)

Now lets divide it with given polynomial (3z - 4)

$\frac{-(2z-7)(3z-4)}{(3z-4)}$

= -(2z - 7) or -2z + 7