Math, asked by harshchhawal233, 16 days ago

please give me full answer please give me correct answer​

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Answered by maheshtalpada412
3

Step-by-step explanation:

Question 4.1

\:  \text{26 kg 50 g =26 kg +50 g }

 \displaystyle \rm 26 kg +\frac{50}{1000} kg \ldots\left[\because 1 gm =\frac{1}{1000} kg \right]

 \rm \: =26 kg +0.050 kg

 \text{ \( \rm =(26+0.050) kg =26.050 kg =26.05 \) \( \rm kg \)}

Question 4.2:-

 \begin{array}{l} 0.008 \\  \displaystyle \rm \implies \frac{8}{1000} \\ \\  \displaystyle \rm \implies \frac{8 \div 8}{1000 \div 8}   \\ \\  \boxed{\red{  \displaystyle \rm  \implies \frac{1}{125} }}\end{array}

Question 6:-

Given that, the grades achieved by 30 students of a class, B, C, C, E, A, C, B, B, D, D, D, D, B, C, C, C, A, C, B, E, A, D, C, B, E, C, B, E, C, D . These marks are represented in the table by using tally marks below as,

\begin{array}{|l|l|l|} \hline \rm Grad & \rm \text{ Tally marks} & \rm \text{ Number of Students} \\ \hline \rm  A&   |||  & 3 \\ \hline \rm B & \bcancel{ || ||}  \:  \:  ||   & 7 \\ \hline \rm C & \bcancel{ | || | }  \:  \:  \bcancel{ | || | }& 10 \\ \hline \rm D & \bcancel{ | || | } \:  \: | & 6 \\ \hline \rm E &  | || |  & 4 \\ \hline \end{array}

Answered by AgrajitDebroy
0

Answer:

Refer to the attached file.

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