please give me full equation solution answer !! urgent
Class 10 th
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Answers
Check ur book answer whether my answer is similar to urs or not
Step-by-step explanation:
i).1/4,-1
Given:
Sum of the zeroes=titha+bita=1/4
product of zeroes=titha*bita=-1
The family polynomial is
= k[x^2-(Sum of zeroes)x+(product of zeroes)]
= k[x^2-(1/4)x+(-1)]
= k[x^2-1/4x-1]
= k[4x^2-1x-4 /4]
= k[4x^2-1x-4]
Taking k =1 .°.the required polynomial is
= 1[4x^2-1x-4]
= 4x^2-1x-4
ii)root2,1/3
Given:
sum of the zeroes=titha+bita=root2
product of zeroes=titha*bita=1/3
The family polynomail is
= k[x^2-(Sum of zeroes)x+(product of zeroes)]
= k[x^2-(root2)x+(1/3)]
= k[x^2-(root2)x+1/3]
= k[3x^2-3(root2)x+1 /3]
= k[3x^2-3(root2)x+1]
Taking k =1 .°.the required polynomial is
= 1[3x^2-3(root2)x+1]
= 3x^2-3(root2)x+1
iii)0,root5
Given:
Sum of the zeroes=titha+bita=0
product of zeroes=titha*bita=root5
The family polynomial is
= k[x^2-(Sum of zeroes)x+(product of zeroes)]
= k[x^2-(0)x+(root5)]
= k[x^2-0x+root5]
Taking k =1 .°.the required polynomial is
=1[x^2-0x+root5]
x^2-0x+root5