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Given, (x)^(3a)^(bc) = x^(bac) can be written as
3a^(bc) = abc
Divide by 3abc on both sides, we get
3a^bc/3abc = abc/3abc
(3a)^bc-1/bc = 1/3.
Hope this helps!
3a^(bc) = abc
Divide by 3abc on both sides, we get
3a^bc/3abc = abc/3abc
(3a)^bc-1/bc = 1/3.
Hope this helps!
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