please give me full solution
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To find the area we use formula..
Thita/360 pi r^2 - 1/2 r^2sin
Thita/360 pi r^2 - 1/2 r^2sin
Answered by
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given radius...r =12cm
theta =120
Area of corresponding segment ....i.e.
Area of minor segment = area of sector -- area of triangle
= pie r ka square theta/360 -- 1/2 r ka square sin thata
=3.14 × 12 ×12 ×120/360 -- 1^2 × 12 ×12 ×sin120
( sin 120° = root3/2)
= 3.14 ×12 × 12 ×120/ 360 --1/2 ×12 ×12 × root3/2 ..
now...after it do calculation urself....still u find any prblm then ask
theta =120
Area of corresponding segment ....i.e.
Area of minor segment = area of sector -- area of triangle
= pie r ka square theta/360 -- 1/2 r ka square sin thata
=3.14 × 12 ×12 ×120/360 -- 1^2 × 12 ×12 ×sin120
( sin 120° = root3/2)
= 3.14 ×12 × 12 ×120/ 360 --1/2 ×12 ×12 × root3/2 ..
now...after it do calculation urself....still u find any prblm then ask
Parul678:
sabas u too
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