Math, asked by 123sona, 1 year ago

please give me full solution

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Answered by nitthesh7
6
The AP is only (i) in these three sequences.

(i) 3, 3 + √2, 3 + 2√2, 3 + 3√2

a = 3

Because each time √2 is added 

d ⇒ 3 + √2 - 3 = √2
   ⇒ 3 + 2√2 - 3 - √2 = √2

Three more terms 

= a + 4d, a + 5d, a + 6d

= a + 4√2, a + 5√2, a + 6√2


But (ii) and (iii) do not form AP, because


(ii) Each time the power increases and this cannot be an AP,

d ≠ a² - a ≠ a³ - a²

(iii) Each time 3 is added inside power and this cannot be an AP

d ≠ √6 - √3 ≠ √9 - √6         ⇒ √6 - 3 ≠ 3 - √6


☺ Hope this Helps 



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Answered by riaagarwal3
6
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