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Train R takes 5 hours less than train S for covering a distance of 750km . If the average speed of train R is 25km/h more than that of train S , find the average speeds of both the trains.
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GauravSaxena01
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Answer:
r = the common speed of train R
r>0
s = the common speed of train S,
s>0
the average speed of train R is 25 km/hr over that of the train S
r = 25 + s
since avgrage speed = distance/time
=> time = distance/avg.speed
train R takes 5 hours but train S for covering a distance of 750 km/h
750/r = 750/s - 5
plug r = 25 + s into the last equation
750/(25 + s) = 750/s - 5
by resolution we discover and contemplate the positive roots
s = 50 km/hr
Average speeds of both train is 50km/hr
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