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SERIOUSLY.
Tommorow is my exam.
Please help me
Answers
Explanation:
Given:
The perimeter of a rectangle is 34 cm
Its breadth is of 5. cm
To find:
The length of each diagonal of it (through Pythagoras theorem)
Solution:
The formulas to be used:
\begin{gathered}\boxed{\bold{Perimeter\:of \:a rectangle = 2[L + B]}}\\\\\boxed{\bold{Diagonal\:of \:a rectangle, D^2 = L^2 + B^2}}\end{gathered}
Perimeterofarectangle=2[L+B]
Diagonalofarectangle,D
2
=L
2
+B
2
Let's assume,
"L" → represents the length of the rectangle
"B" → represents the breadth of the rectangle = 5 cm
The perimeter of the rectangle = 34 cm
∴ 2[L + B] = 342[L+B]=34
substituting the value of B = 5 cm, we get
\implies 2 [L + 5] = 34⟹2[L+5]=34
\implies L + 5 = 17⟹L+5=17
\implies L = 17 - 5⟹L=17−5
\implies \bold{L = 12}⟹L=12
∴ Each diagonal of the rectangle is,
= \sqrt{L^2 + B^2} = \sqrt{12^2 + 5^2} = \sqrt{144 + 25} = \sqrt{169} = 13\:cm
L
2
+B
2
=
12
2
+5
2
=
144+25
=
169
=13cm
Thus, the length of each diagonal of the rectangle is → 13 cm.
Please mark me brainlest.....
Answer:
13cm
Explanation:
given perimeter of rectangle= 34cm
given breadth= 5cm
we know perimeter of a rectangle= 2(l+b)
→ 2(l+5) = 34
→ l+5 = 34/2
→ l+5= 17
→ l= 17-5
→ l= 12cm
therefore we have length as 12cm and breadth as 5cm,
taking two adjacent sides and a diagonal which is connecting both it forms a right angled triangle.
(that is AB, BC are the adjacent sides, AC the diagonal based on diagram)
Using Pythagoras Theorem
Diagonal^2 = length2 + breadth2
= 12^2 + 5^2
= 144 + 25
= 169
diagonal = √169
= 13cm
Therefore each diagonal is of length 13cm
pls mark my answer as brainliest for my effort for you!