Question

please give me right answer and do fast⏳⏳⏳⏳​

Answer 1

Step-by-step explanation:

let...smallest no. be x ...then nest no. aee...x+2 and x+4

a/q

3x-7=2×(x+4)

3x-7=2x+8

x=15

the....no. are=15,17,19

Answer 2

ANSWER:8

Given:

Three times the smallest of three consecutive odd number decreased by 7 equal twice the largest one.

To find:

The number.

Solution:

Let three consecutive odd numbers be x, x+2 ,x+4.

⚫Smallest consecutive number is x.

⚫Largest consecutive number is x+4.

According to the question:

=) 3x -7= 2(x+4)

=) 3x -7 = 2x + 8

=) 3x - 2x= 8 +7

=) x =15

So,

⚫First number is 15.

⚫Second number is, x +2 = 15 +2 = 17

⚫Third number is, x+4 = 15 +4 = 19.

ANSWER:9;

⚫Let the digit at one's place be R &

⚫Let the digit at ten'e place be 3R.

⚫Original number is 10(3R) + R

⚫Reversed number is 10R + 3R

According to the question:

=) 10(3R) + R + 10R + 3R= 88

=) 30R + R + 10R + 3R = 88

=) 44R = 88

=) R= 88/44

=) R= 2

So,

The original number is 10(3×2) + 2

=) 10× 6 + 2

=) 60 +2

=) 62

Hope it helps ☺️