Math, asked by divyanshi8797, 9 months ago

please give me solution


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Answers

Answered by pushpabajnikathayat3
1

a) 3 × 3^4 × 2^5/2 × 4^2

Ans. 3 × 3^4 × 2^5/2 × (2^2)^2

= 3^1+4 × 2^5/2 × 2^4

=3^5 × 2^5/2^1+4

=3^5 × 2^5/2^5

=3^5 × 2^5 - 5

=3^5 × 2^0

=3^5 × 1

=3^5

or

=3 × 3 × 3 × 3 × 3

=243

b) [(4^3)^2 × 4^4] ÷ 4^14

Ans. [4^6 × 4^4] ÷ 4^14

= [4^6 + 4] ÷ 4^14

= 4^10 ÷ 4^14

= 4^10 - 14

= 4^-4

= 1/4^4

or

= 1/4 × 4 × 4 × 4

= 1/256

c) 8^3 × a^5 × b^2/2^6 × a^3 × b

Ans. (2^3)^3 × a^5 - 3 × b^2 - 1/2^6

= 2^9 × a^2 × b/2^6

= 2^9 - 6 × a^2 × b

= 2^3 × a^2 × b

= 2 × 2 × 2 × a^2 b

= 8a^2 b

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