Question

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Answer 1

Answer:

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Answer 2

Answer:

Given

Suppose the given number is 10x + y

& the number obtained by reversing the order of digits is 10 y + x

We know that

                         

                    $x+y=9$    ⇒ Equation 1

                       &

               $10x+y-27=10y +x$

Now we can simplify the above equations

              $10x+y-27= 10y+x\\ \\=9x-27=9y\\\\= 9x-9y=27\\\\=9(x-y)=27$

       

Therefore,

                  x - y = 3   ⇒  Equation 2

Adding both equations,

     (x + y) + (x - y) = 12

           = 2x = 12

                x = 6

Now,

         

         x + y = 9

         6 + y = 9

So,

       

       y = 3

The given numbers are

          10x + y = 10 × 6 + 3

                       =  63

           

          10y + x = 10 × 3 + 6

                       = 36

Checking,

            y = 3

            x = 6

       

         3 + 6 = 9 ⇒ Equation 1

          6 - 3 = 3 ⇒Equation  2

       63 - 27 = 9

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