Question

please give me solution to above problem please solve on paper and send me photo very urgent !!!!

Answer 1

Hi friend,
sum of slopes and product of slopes of equation ax²+2hxy+by²=0 is 
-2h/b and a/b respectively.
given that m₁=4m₂
Sum of slopes is =m₁+m₂=-2h/b
                         ⇒5m₂=-a/b
Squaring on both sides 25m₂²=4h²/b²----------------------equation 1
Now,product of slopes is m₁m₂=a/b
                  ⇒ 4m₂²=a/b
                       m₂²=a/4b
Substituting m₂² in equation 1
                      25(a)/4b=4h²/b²
                     25ab=16h²
HOPE THIS HELPS.............

Answer 2

I have done this by taking the equation of lines as y+mx=0 you can also cosider it as y-mx=0, and kindly go through the solution, you will enjoy it.