Question

please give me step by step answer option 1= x²+13x+42=0 ,2 = x²-13x+42=0 ,3= x²-13x-42=0 ,4=x²-x+42=0​

Answer 1

Answer:

So the option is 1

Hope this is useful

Answer 2

Answer:

option 2

Step-by-step explanation:

it is given that the roots are 6 and 7----------------(1)

and we also know that every quadratic equation is of the form

$ax ^{2} + bx + c = 0$

where

sum of the roots is ----------(2)

$\frac{ - b}{ a}$

and product of roots is -----------------(3)

$\frac{c}{a}$

therefore ,

the quadratic equation can be simplified as (dividing by a )

$\frac{ax^{2} - ( - bx) + c }{a} = 0$

which gives,

$x ^{2} - ( - \frac{b}{a} x) + \frac{c}{a} = 0$

that is

from 2 and 3

${x}^{2} - (sum \: of \: the \: roots)x + (product \: of \: the \: roots) = 0$

sum of the roots is 6+7=13

and product of the roots is 6×7=42

therefore answer is

${x}^{2} - 13x + 42 = 0$