Question

please give me step by step solution​

Answer 1

Answer:

Given: A pentagon ABCDE

MC = AC – AM = 18 – 14 = 4 cm

MN = AM – AN = 14 – 6 = 8 cm

Here,

Area (Pent. ABCDE) = area(AEN+area(DMC) + area(ABC) +area(Trap. DMNE)

Area of triangle =1/2× (base) × (height).

Area of trapezium is1/2× (sum of parallel sides) × height

Here,

Area (AEN) =1/2× (AN) × (EN) =1/2× (6) × (9) = 27 cm2.

Area (DMC) =1/2× (MC) × (DM) =1/2× (4) × (12) = 24 cm2.

Area (ABC) =1/2× (AC) × (BL) =1/2× (18) × (4) = 36 cm2.

Area (Trap. DMNE) =1/2× (DM + EN) × MN =1/2× (12 + 9) × 8 = 84 cm2.

Area (Pent. ABCDE) = area (AEN) + area (DMC) + area (ABC) + area (Trap. DMNE)

= 27 + 24 + 36 + 84 = 171 cm2.

Area (Pent. ABCDE) = 171 cm2.