please give me step by step solution .
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=(x^2+3x+2x+6)/x^2-9
=x(x+3)+2(x+3)/x^2-9
=(x+3)(x+2)/(x+3)(x-3)
=(x+2)/(x-3)
Now for range put minimum value of and maximum value of x.
=x(x+3)+2(x+3)/x^2-9
=(x+3)(x+2)/(x+3)(x-3)
=(x+2)/(x-3)
Now for range put minimum value of and maximum value of x.
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2
Look in attachment ………
for range put value of x
for range put value of x
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