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Given
- A piece of wire is bent in shape of a square of side 11 cm. it is rebent to form a circular ring.
To find
- Diameter of the ring
Solution
- Side of square = 11cm
- Perimeter of square = 4×11=44cm
- Circumference of Circle = 2×pi×r
- 44=2×pi×r
- 44÷2=pi×r Note: pi=22÷7 or 3.14
- 22=(22÷7)×r
- r=(7÷22)÷22
- r=7
So, Diameter = 7×2=14
Answered by
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Side of square = 11 cm
Perimeter of square = 4 × 11 = 44 cm
Circumference of circle = 2 × pi × r
44 = 2 × pi × r
44 ÷ 2 = pi × r Note: pi = 22 ÷ 7 Or 3.14
22 = ( 22 ÷ 7 ) × r
r = ( 7 ÷ 22 ) ÷ 22
r = 7
So, Diameter = 7 × 2 = 14.
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