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Because 1+Tan²Ф = Sec²Ф,
L.H.S ≡ (Sec²Ф-1)² +Sec²Ф-1
≡ Sec4Ф - 2Sec²Ф + 1 + Sec²Ф- 1
≡ Sec4Ф - Sec²Ф ≡ R.H.S
Hence,proved.
Note that Sec4Ф is sec Ф to the power of 4.There's no way to indicate that in standard way.
shubham610:
ur ans is wrong
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ⓗⓔⓨ ⓜⓐⓣⓔ ! ___________________________________________________________________________
Proved||| Above . Refer to attachment
----HLP
---THANXXX...
Proved||| Above . Refer to attachment
----HLP
---THANXXX...
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