Question

please give me the ans . plz guys !! ​

Answer 1

x = $\frac{-b+\sqrt{b2-4ac} }{2a}$

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

$5x^{2}$ - 3x - 4= 0

a= 5

b= -3

c= -4

x= $\frac{-(-3)+\sqrt{(-3)2-4*5(-4)} }{2*5}$

x= $\frac{3+\sqrt{9-4*5(-4)} }{2*5}$

x= $\frac{3+\sqrt{9+80} }{2*5}$

x= $\frac{3+\sqrt{89} }{2*5}$

Rearrange and isolate the variable to find each solution

x= $\frac{3-\sqrt{89} }{10}$

Final answer= $\frac{3+\sqrt{89} }{10}$