Question

please give me the ans plzzzzz ​

Answer 1

Given

• AB = 5 cm
• ∠A = 3x
• ∠B = 2x
• ∠C = x

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To Find

• The value of 'x' in the interior angles.
• The value of AC
• The value of BC

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Solution

Firstly, we will find the value of 'x' in the interior angle. So we know the the sum of all angles in any type of triangle is 180°, so we will solve the this equation ⇒ x + 2x + 3x = 180

Let's solve your equation step-by-step

x + 2x + 3x = 180

Step 1: Add the LHS.

⇒ x + 2x + 3x = 180

⇒ 6x = 180

Step 2: Divide 6 from both sides of the equation.

⇒ 6x ÷ 6 = 180 ÷ 6

⇒ x = 30

∴ The value of 'x' is 30°.

∠A ⇒ 3x = 3×30 = 90

∠B ⇒ 2x = 2×30 = 60

∠C ⇒ x = 30

Now, we have to find AC & BC.

Let's find AC first.

⇒ tan60° = $\frac{AC}{AB}$

⇒ √3 = $\frac{AC}{5}$

⇒ AC = 5√3 cm

∴ The value of AC is 5√3 cm

Let's find BC next.

⇒ cos60° = $\frac{AB}{BC}$

⇒ $\frac{1}{2} =\frac{5}{BC}$

⇒ $BC = 5(2)$

⇒ BC = 10 cm

∴ The value of BC is 10 cm

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Answer 2

question:

from the information given in the figure.find the value of x and also find AC and BC.

solution:

$\purple{ \sf x=30 \degree , AC = 5 \sqrt{3} , BC = 10cm}$

Given:

figure.

To find:

values of x,AC and BC?

step by step explanation:

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let's find x:

$\sf as \: we \: know : \sf{sum \: of \: all \: angles \: of\: a \: triangle \: = 180 \degree}$

$\implies \sf x + 2x + 3x = 180 \degree$

$\implies \sf 6x = 180 \degree$

$\implies \sf x = \frac{180}{6}$

$\implies \sf x = 30 \degree$

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let's find AC:

$\implies\sf \sqrt{3} = \frac{AC}{AB}$

$\implies \sf \sqrt{3} = \frac{AC }{5}$

$\implies\sf AC = 5 \sqrt{3}$

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let's find BC:

$\implies \sf \frac{1}{2} = \frac{AB}{BC}$

$\implies \sf \frac{1}{2 } = \frac{5}{ BC }$

$\implies \sf BC = 5(2)$

$\implies \sf BC = 10cm$

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therefore:

$\red{ \sf x=30 \degree , AC = 5 \sqrt{3} , BC = 10cm}$