please give me the answer
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Answer:
atoms in 40g of na = 6×10^23
atoms in 120g of na = 6×10^23 ×120 / 40
= 18×10^23 atoms
atoms in 56g fe = 6×10^23
atoms in 120g fe= 6×10^23×120/56
= 12.85×10^23 atoms
Explanation:
therefore na has more no. of atoms
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Answer:
So, number of atoms in 3 moles of Ca = 3 × 6.022×10^23 atoms. So, 120 g of Calcium has more atomsthan 120 g of Iron. =5.179 ×10^23 atoms.
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