Chemistry, asked by bhramarbar15, 7 months ago

please give me the answer​

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Answered by mananmakkar2004
2

Answer:

atoms in 40g of na = 6×10^23

atoms in 120g of na = 6×10^23 ×120 / 40

= 18×10^23 atoms

atoms in 56g fe = 6×10^23

atoms in 120g fe= 6×10^23×120/56

= 12.85×10^23 atoms

Explanation:

therefore na has more no. of atoms

Answered by shreyasthegreat
1

Answer:

So, number of atoms in 3 moles of Ca = 3 × 6.022×10^23 atoms. So, 120 g of Calcium has more atomsthan 120 g of Iron. =5.179 ×10^23 atoms.

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