Question

please give me the answer 33 and 34 question

Answer 1

this may help u...........

Answer 2

sec37/cosec53 + 2cot15 cot25 cot45.cot75 cot65 -3 (sin^2 18 + sin^2 72)

= sec (90-53)/cosec53 + 2cot (90-75)cot (90-65) - 3 (sin^2 (90-72) + sin^2 72)

= cosec53/cosec53 + 2Tan75 Tan65 cot45 cot75 cot65 -3 (cos^2 72 + sin^2 72)

As Tan.Cot = 1

= 1 + 2 - 3 (1)

= 0

Thanks