Math, asked by pratikwazire, 2 months ago

please give me the answer

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Answered by induu2345

1

Answer:

(secA-tanA) 2 = (1/cosA-sinA/cosA)2

(1-sinA/cosA)2

(1-sinA)2/(cosA)2

(1-sinA)2/(1-sin2A)

(1-sinA)2/(1-sinA)(1+sinA)

1-sinA/1+sinA = RHS

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