please give me the answer
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hey bro
#ur Ans
___________
let the first square side be X, and
second be (X+5)
so
sum of area
x^2 + (X+5)^2 = 325
x^2 +x^2 +25 +10x = 325
2x^2 +10x = 325-25
2x^2 +10x -300 = 0
x^2 +5x -150 = 0
Now factorise
x^2 +15x -10x -150 =0
X (X+15) -10 ( X +15) =0
(X -10) (X+15) =0
X = 10, -15
X can not be negative
so
X = 10
side of small square = 10cm
side of bigger square =(X+5) = 15cm
✌✌☺☺
#ur Ans
___________
let the first square side be X, and
second be (X+5)
so
sum of area
x^2 + (X+5)^2 = 325
x^2 +x^2 +25 +10x = 325
2x^2 +10x = 325-25
2x^2 +10x -300 = 0
x^2 +5x -150 = 0
Now factorise
x^2 +15x -10x -150 =0
X (X+15) -10 ( X +15) =0
(X -10) (X+15) =0
X = 10, -15
X can not be negative
so
X = 10
side of small square = 10cm
side of bigger square =(X+5) = 15cm
✌✌☺☺
JaganathRath:
Thank you very much
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