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Given : A circle of centre O, diameter BC and OD perpendicular to chord AB.
Since OD is ⊥ to chord AB
D is the midpoint of AB (perpendicular drawn from the centre to a chord bisects the chord)
O is the centre
O is the midpoint of diameter BC
In ΔABC, O and D are the midpoints of BC and AB respectively
OD ∥ AC
OD = CA2
(segment joining the midpoints of two sides of a triangle is half of the third side)
CA = 2OD
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