Question

Please give me the answer...

Answer 1

$hi \: mate$


tanA=2
=sec²A-tan²A=1
= sec²A=1+tan²A
=sec²A=1+4
= secA=√5
=, cosA=1/secA=1/√5
Again, sin²A+cos²A=1
= sin²A=1-cos²A
=sin²A=1-1/5
= sin²A=4/5
= sinA=2/√5
= cosecA=1/sinA=√5/2
= secA.sinA+tan²A-cosecA
=√5.2/√5+(2)²-√5/2
=2+4-√5/2
=6-√5/2