please give me the answer abhi
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as981600:
x3+x2=4y+6 === x+3=0 there fore x= -3 so -3 Ka whole cube = -27 + (-3) whole sq = 9 so -27+9=4y+6 so -27+9= -18. so -18=4y+6 there fore -18-6 =4y. so thus -12=4y therefore -12/4 = y. answer is -3 = y
oh sorry bro I saw that there was equal 2. but there was minus sorry for wrong answer
Answers
Answered by
1
Heya !!!
Let X + 3 is a factor of the given polynomial.
So,
X + 3 = 0
X = -3
P ( X ) = X³ + X² - 4X + 6
=> X³ + X² - 4X + 6 = 0
Putting X = -3 in P(X).
P(-3) = (-3)³ + (-3)² - 4 × -3 + 6
=> -27 + 9 + 12 + 6
=> ( 27 ) - ( 27 )
=> 0
Remainder = 0
So,
( X + 3 ) is a factor of the given polynomial.
★ HOPE IT WILL HELP YOU ★
Let X + 3 is a factor of the given polynomial.
So,
X + 3 = 0
X = -3
P ( X ) = X³ + X² - 4X + 6
=> X³ + X² - 4X + 6 = 0
Putting X = -3 in P(X).
P(-3) = (-3)³ + (-3)² - 4 × -3 + 6
=> -27 + 9 + 12 + 6
=> ( 27 ) - ( 27 )
=> 0
Remainder = 0
So,
( X + 3 ) is a factor of the given polynomial.
★ HOPE IT WILL HELP YOU ★
Answered by
3
If (x + 3) is the factor of the given equation, Remainder must be 0,
By Remainder Theorem,
(x + 3) = 0
x = -3
x³ + x² - 4x + 6
=> (-3)³ + (-3)² - 4(-3) + 6
=> -27 + 9 +12 + 6
=> 0
As remainder is 0, ( x + 3 ) is the factor.
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