Question

please give me the answer and how to do it and i will mark you the
$x = \frac{x + 1}{5} - \frac{x - 2}{4}$
brainliest​

Answer 1

Answer:

★ǫᴜᴇsᴛɪᴏɴ★

Solve :-

$\small \bf x = \dfrac{x + 1}{5} - \dfrac{x - 2}{4}$

★ANSWER★

$\small \bf x = \dfrac{x + 1}{5} - \dfrac{x - 2}{4}$

★ On taking LCM on RHS, we get

$\small \bf x \: = \dfrac{4(x + 1) - 5(x - 2)}{20}$

$\bf \implies \: \: x \: = \dfrac{4x + 4 - 5x + 10}{20}$

$\bf \implies \:x = \dfrac{14 - x}{20}$

$\bf \implies \: \: 20x = 14 - x$

★ On transposing

$\bf \implies \:20x + x = 14$

$\bf \implies \:21x = 14$

$\bf \implies \:x = \dfrac{14}{21} = \dfrac{2}{3}$

$\underline{\boxed{\sf Verification}}$

★ Consider RHS

$\small \bf \dfrac{x + 1}{5} - \dfrac{x - 2}{4}$

$\small \bf ⟹\dfrac{ \dfrac{2}{3} + 1 }{5} - \dfrac{ \dfrac{2}{3} - 2}{4}$

$\bf \implies \: \dfrac{2 + 3}{3 \times 5} - \dfrac{2 - 6}{3 \times 4}$

$\bf \implies \: \dfrac{1}{3} - \dfrac{( - 1)}{3}$

$\bf \implies \: \dfrac{1}{3} + \dfrac{1}{3}$

$\bf \implies \: \dfrac{2}{3}$

$\bf \implies \:LHS$