Question

please give me the answer as soon as possible ​

Answer 1

Answer:

$4x {}^{3} y \div 2xy = 2 {x}^{2} \\ 12x \div ( - 3 {x}^{2} ) = \frac{ - 4}{x} \\ 4p \div 9pq = \frac{4}{9q} \\ ( - 33 {a}^{3} {b}^{2} c) \div ( - 11 {a}^{2} {b}^{2} {c}^{3} ) = \frac{3a}{ {c}^{2} }$