Question

please give me the answer for my homework​

Answer 1

$\bold{\underline{\underline{Answer:}}}$

•°• First part (x) = 15

Second part (x+10) = 25

$\bold{\underline{\underline{Step\:-\:by\:-\:step\:explanation:}}}$

• We have the number 40 and we need to divide it into two parts.

To find :

• Other number which is 10 more than the other.

Solution :

Let the first number be x.

Let the second number be x + 10

Number = 40

Now, if we sum up first number and second number, their result will be 40.

Let's constitute it mathematically,

$\rightarrow$ $\bold{x+x+10=40}$

$\rightarrow$ $\bold{2x+10=40}$

$\rightarrow$ $\bold{2x=40-10}$

$\rightarrow$ $\bold{2x=30}$

$\rightarrow$ $\bold{x={\dfrac{30}{2}}}$

$\rightarrow$ $\bold{x = 15}$

•°• The first number = x = 15

Second number = x + 10

Second number = 15 + 10

Second number = 25

Answer 2

$\huge\mathfrak{Answer :-}$

We neee to divide 40 into two parts such that one part is 10 more than the other..

Let the first number be x

The second number is (x + 10)

According to problem ,

x + x + 10 = 40

2x = 40 - 10

2x = 30

x = 30/2

x = 15

The first part is 15.

The second part is 15 + 10

= 25