Math, asked by Prenjaiswal2424, 11 months ago

please give me the answer for my homework​

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Answered by Anonymous
150

\bold{\underline{\underline{Answer:}}}

•°• First part (x) = 15

Second part (x+10) = 25

\bold{\underline{\underline{Step\:-\:by\:-\:step\:explanation:}}}

• We have the number 40 and we need to divide it into two parts.

To find :

  • Other number which is 10 more than the other.

Solution :

Let the first number be x.

Let the second number be x + 10

Number = 40

Now, if we sum up first number and second number, their result will be 40.

Let's constitute it mathematically,

\rightarrow \bold{x+x+10=40}

\rightarrow \bold{2x+10=40}

\rightarrow \bold{2x=40-10}

\rightarrow \bold{2x=30}

\rightarrow \bold{x={\dfrac{30}{2}}}

\rightarrow \bold{x = 15}

° The first number = x = 15

Second number = x + 10

Second number = 15 + 10

Second number = 25

Answered by Anonymous
40

\huge\mathfrak{Answer :-}

We neee to divide 40 into two parts such that one part is 10 more than the other..

Let the first number be x

The second number is (x + 10)

According to problem ,

x + x + 10 = 40

2x = 40 - 10

2x = 30

x = 30/2

x = 15

The first part is 15.

The second part is 15 + 10

= 25

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