please give me the answer of 7th one. it's urgent. don't send wrong❌ one kk
Attachments:
Answers
Answered by
3
we know that in an isosecless triangle the angles opposite to equal sides are equal
therefore
<BAC +ABC + ACB = 180°----->
BAC + 2ABC = 180
60 + 2ABC = 180
ABC = ACB = 180-60/2
------> 60°
Similarly...
BDC + 2DBC = 180 ( DBC=DCB)
DBC = DCB = 180-40/2
------> 70°
angle ABD = 60 + 70 = 130°
angle ACD = 60 + 70 = 130°
so, ABC = ACD
therefore
<BAC +ABC + ACB = 180°----->
BAC + 2ABC = 180
60 + 2ABC = 180
ABC = ACB = 180-60/2
------> 60°
Similarly...
BDC + 2DBC = 180 ( DBC=DCB)
DBC = DCB = 180-40/2
------> 70°
angle ABD = 60 + 70 = 130°
angle ACD = 60 + 70 = 130°
so, ABC = ACD
Similar questions