Question

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Answer 1

$\: \huge\orange{answer}$

Relationship between Kelvin and Fahrenheit is

y = 9/5 (x - 273) + 32 ...(1)

i)

Given that, x = 313 K

From (i), we get

y = 9/5 (313 - 273) + 32

= 9/5 (40) + 32

= (9 × 8) + 32

= 72 + 32

= 104

Therefore, the temperature of the liquid in

Fahrenheit scale be 104°F

ii)

Given that, y = 158° F

From (1), we get

158 = 9/5 (x - 273) + 32

or, 9/5 (x - 273) = 158 - 32

or, 9/5 (x - 273) = 126

or, x - 273 = 5/9 (126)

or, x - 273 = (5 × 14)

or, x = 70 + 273

or, x = 343

Therefore, the temperature of the liquid in Kelvin scale be $\fbox{343\:K}$

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Answer 2

answer of the question.