Please give me the answer of no 68
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Area of right triangle=1/2×BasexHeight
Let Base=a
Therefore Altitude=a+7
165=1/2×a×(a+7)
330=a^2+7a
a^2+7a-330=0
a^2+22a-15a-330=0
a(a+22)-15(a+22)=0
(a-15)(a+22)=0
Therefore a=15 as a cannot be -22 (a cannot be negative)
Therefore Base=15
Altitude=15+7=22
Hope it's helpful! Please mark me brainliest!!
Let Base=a
Therefore Altitude=a+7
165=1/2×a×(a+7)
330=a^2+7a
a^2+7a-330=0
a^2+22a-15a-330=0
a(a+22)-15(a+22)=0
(a-15)(a+22)=0
Therefore a=15 as a cannot be -22 (a cannot be negative)
Therefore Base=15
Altitude=15+7=22
Hope it's helpful! Please mark me brainliest!!
Srkfan:
how altitude will be a+7
Bro I told you its given in question..
give me the answer
how base and altitude is similar to latter and former
The latter (Altitude) excceds former(Base) by 7.
Latter means which is stated afterwards and former means before.
thanks bro
Your welcome
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