please give me the answer of the question in given photo
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X +Y =11
10Y+X+9=10X+Y
X-Y=1
X=6 Y=5
65
10Y+X+9=10X+Y
X-Y=1
X=6 Y=5
65
Answered by
1
let the ones digit be x and tens digit be y.therefore the no.=10y+x
according to the question,
x+y=11 ___(1)
10y+x+9=10x+y
9y-9x+9=0
or x-y-1=0 ___(2)
now we can solve the set of these equations using any of the suitable method (here I have chosen the substitution method).
from eq (1) x=11-y
putting the value of x obtained by eq(1) in eq (2):-
11-y-y-1=0
10-2y=0
5-y=0
therefore, y=5 and x=11-y=11-5=6 so the number=65
thank u, hope it helps!^_^
according to the question,
x+y=11 ___(1)
10y+x+9=10x+y
9y-9x+9=0
or x-y-1=0 ___(2)
now we can solve the set of these equations using any of the suitable method (here I have chosen the substitution method).
from eq (1) x=11-y
putting the value of x obtained by eq(1) in eq (2):-
11-y-y-1=0
10-2y=0
5-y=0
therefore, y=5 and x=11-y=11-5=6 so the number=65
thank u, hope it helps!^_^
Millo:
i am not in 10th standard
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