Question

Please give me the answer of this question​

Answer 1

→ Diagonals if a parallelogram divide it into 4 triangles is equal area.

→ And also diagonals divide the parallelogram into 4 triangles such that

→ Pair of opposite triangle are congruent..

→ We know that diagonals of a parallelogram bisect each other.

→ When you consider ∆ABC , BO is median

→ So median divide the triangle into 2 equal triangles of equal area.

→ So all the 4 smaller triangles are equal in area.

→ When you see pair of opposite triangles

→ They are congruent so the called it as 4 congruent triangles.

HOPE IT HELPS

Answer 2

Step-by-step explanation:

GIVEN- ABCD is a //gm

To prove - ΔAOB ~ ΔBOC ~ ΔCOD ~ ΔDOA

Proof - In ΔAOB & ΔCOD

.LBOA = LDCO(alternate interior angle)

AB =CD(opp. sides are equal)

LABO=LCDO(alternate interior angle)

Therefore, ΔAOB~ΔCOD by AAS congruence

Similary ΔAOD~ΔBOC~ΔCOD~ΔDOA

Hence proved