Question

please give me the answer of this question ​

Answer 1

Area of Quadrilateral ABCD

= Area of Triangle ABD + Area of Triangle CDB

Area of Triangle ABD = 1/2 × Base

× Height

= 1/2 × 10 × 4

= 20 cm^2

Area of Triangle CDB = 1/2 × Base

× Height

= 1/2 × 10 × 4

= 20 cm^2

Now ,

Area of Quadrilateral ABCD =

Area of Triangle ABD + Area of Triangle CDB

Area of Quadrilateral ABCD = 20 + 20 cm^2

Area of Quadrilateral ABCD = 40 cm^2

Hence option B is correct

I Hope it will help you

Thank s..

Answer 2

Answer:

40 cm²

Step-by-step explanation:

Area of ∆ABD = 1/2 × base × height

= (1/2 × 10 × 4) cm²

= 20 cm²

Area of ∆BCD = 1/2 × base × height

= (1/2 × 10 × 4) cm²

= 20 cm²

Now, area of quad. ABCD = Ar. of ∆ABD + Ar. of ∆BCD

= 20 cm² + 20 cm²

= 40 cm²

Hence, area of the quadrilateral ABCD is 40 cm².