Question

please give me the answer​ plz

Answer 1

Step-by-step explanation:

LHS

2log(x-y) = log(x-y)^2 = log(x^2+y^2-2xy)

RHS

3log7+logx+logy = log 7^3 +log(xy)= log(343xy)

therefore,

log (x2+y2-2xy )= log 343xy

x^2+y^2= 345xy

PROVED

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Answer 2

Answer:

Please see the attachment..