Question

please give me the answer


Use a suitable identity, find the square of xy + 32)​

Answer 1

Answer:

Given that: x + y = 12 and xy = 32 Using the identity, (x + y)^2 = x^2 + 2xy + y^2 (12)^2 = x^2 + 64 + y^2 144 = x^2 + y^2 + 64 144 - 64 = x^2 + y^2 80 ...

Answer 2

Answer:

Given that:  x+y=12 and xy = 32

Using the identity, (x+y)2 = x2+2xy+y2

⇒ (12)2 =x2+64+y2

⇒ 144 = x2+y2+64

⇒ 144−64 = x2+y2

⇒ 80 = x2+y2

The answer is x2+y2 = 80