please give me the brief solution of question no. 16
Please if you don't know , then don't type useless things....
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Answer:
magnitude of dipole moment, P = 4uC.m
= 4 × 10^-6 C.m
separation between midpoint of dipole to point of observation, r =√(3-0)² + (4 - 0)² = 5m [ here we assume midpoint of dipole is located at origin.]
angle made by r to dipole axis, θ = tan^-1(4/3) or cos^-1(3/5)
★ using formula
electrical Potential = KPcosθ/r²
= 9 × 10^9Nm²/C² × 4 × 10^-6C.m × cos(cos^-1(3/5))/(5m)²
= 36 × 10³ × (3/5)/25 volts
= (108/125) × 10³ Volts
= 0.864 × 10³ volts
= 864 volts.
hence, electrical potential due to the dipole at (3, 4) in x-y plane is 864 volts
REFER TO ATTACHMENT FOR GRAPH ❤️
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